In LTE, when a UE wants to communicate with an
eNodeB (cell), one of the first things it has to do is get its timing adjusted using
PRACH (Physical Random Access Channel) procedure. Why do we have to adjust the
timing for the UE in LTE? To answer this question let us look at the following scenario:
UE1 is located near the cell edge and UE2 is
located closer to the eNodeB as shown in the diagram. Both the UEs need to
access the network for services and to do that they will first use the PRACH to
initiate communications with the eNodeB. The PRACH is a collision based common
Uplink (UL) channel used by all UEs in a cell to first communicate with the
eNodeB. During this critical first communication the eNodeB will give the UE
three important pieces of information:
1. a temporary
identifier (C-RNTI)
2. permission to
transmit on the UL (Grant)
3. ADJUST the UEs
UL transmission time
Given this scenario (if we do not make any adjustments) the following will happen. Let us look at the timeline starting at subframe t and ending at subframe t+1 at the eNodeB. Lets assume that the eNodeB allocates Resource Block 3 on the UL for the subframe starting at time t to UE1.
- Since UE1 receives the signal from eNodeB with a propagation delay of δ1, UE1's UL transmission time for subframe t will start at time (t+ δ1) with respect to eNodeB
- UE1 receives UL allocation for subframe starting at time t, its transmission will be received by eNodeB starting at time (t+δ1+δ1) since UL transmission will also experience propagation delay (assumed to be equal for DL and UL)
- Effectively the UE1's UL transmission for the subframe t will be received at the eNodeB starting at {t+(2*δ1)} and ending at {(t+1) + (2*δ1)}
- Since UE2 receives the signal from eNodeB with a propagation delay of δ2, UE2's UL transmission time for subframe starting at (t+1) will start at time {(t+1) + δ2} with respect to eNodeB
- UE2 receives UL allocation for subframe (t+1), its transmission will be received by eNodeB starting at time {(t+1)+δ2+δ2} since UL transmission will also experience propagation delay (assumed to be equal for DL and UL)
- Effectively the UE2's UL transmission for the subframe (t+1) will be received at the eNodeB starting at {(t+1) + (2*δ2)} and ending at {(t+2) + (2*δ2)}
When the PRACH preambles are sent, the eNodeB will
measure the arrival delay for each UE and convey to each UE (via MAC signaling)
the amount of timing adjustment it must do prior to its next transmission. For
example, if UE1 and UE2 advance their timing and start their UL transmissions earlier
by 2δ1 and 2δ2 respectively, their transmissions will be received at the
appropriate subframe start and end times. This will prevent any collisions and
interference with their transmissions.
No comments:
Post a Comment